[R] summarizing matrix data

[Henrique Dallazuanna]

On 02/03/2008, Emilio Gagliardi <emilio at ualberta.ca> wrote:
> Henrique,
>
> Again, thank you very much for your code snippets, I am learning from them,
> but they are also creating as many questions as answers...
>
> On Sun, Mar 2, 2008 at 11:48 AM, Henrique Dallazuanna <wwwhsd at gmail.com>
> wrote:
>
> > Then you can try this:
> >
> > apply(array(as.vector(sapply(patt, get)), dim = c(dim(get(patt[1])),
> > ngroups, nsubs)), 1:3, mean)
> >
> >
> > For create the matrices in a loop one option is:
> >
> > lapply(seq(1, 51, by=10), function(x)matrix(seq(x, x+8), nrow=3, ncol=3))
> >
>
> if I use the above code, I get back a list of matrices, which is awesome!
> The problem is that your code to get the means doesn't work on it (
> apply(array(as.vector(...))...additionally, I'm not creating the data, but
> reading it in, file by file and I don't know what group to assign a file
> until I open it (group2, group4, group4,group1,group3,group2,group1,etc)
>
> so I have 120 files to open and process and each file can be assigned to 1
> of 4 groups(or lists as your code demonstrates)...but I don't know until I
> open the file which group hence my loop and meta structure approach. So I
> need to open the file, create a matrix from it (which I have working), store
> it along with other data from the same group, and then after I've read all
> the files and associated the data with a group, then I can generate the
> means per cell.
>
> So I can create 4 lists of matrices, which is fine by me but I don't see how
> I extend your code snippets to the case of reading the data from files...I
> currently have 1 "master" matrix which holds all the subject data as I
> mentioned in my previous post.
> data[3,3,1,nsubjects] represents all the subject data in group 1
> data[3,3,2,nsubjects] represents all the subject data in group 2
> data[3,3,3,nsubjects] represents all the subject data in group 3
>
> how do i pullout just one group's worth of data and apply the mean function
> to each cell ?
> group1 <- get(data[,,1,] ?

Here, don't needed 'get' :

group1 <- data[,,1,]
mean1 <- apply(group1, 1:2, mean)

> group2 <- get(data[,,2,] ?
> mean1 <- apply(group1,1:3,mean) # mean per cell, so nine means (3 x 3) for
> each group...
> mean2 <- apply(group2,1:3,mean) # mean per cell, so nine means (3 x 3) for
> each group...
>
> thanks so much for your patience!
> emilio
>
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>
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--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O