[R] an efficient pairwise matrix cell's comparison function
jim holtman
jholtman at gmail.com
Sun Mar 2 13:18:50 CET 2008
Does this do what you want?
> A <- matrix(sample(0:2, 25, TRUE), ncol=5)
> B <- matrix(1:25, ncol=5)
> C <- ifelse(A == 0, 0, B)
> A
[,1] [,2] [,3] [,4] [,5]
[1,] 1 1 1 2 1
[2,] 1 0 1 1 0
[3,] 0 0 1 0 2
[4,] 0 1 2 0 0
[5,] 1 2 1 2 2
> B
[,1] [,2] [,3] [,4] [,5]
[1,] 1 6 11 16 21
[2,] 2 7 12 17 22
[3,] 3 8 13 18 23
[4,] 4 9 14 19 24
[5,] 5 10 15 20 25
> C
[,1] [,2] [,3] [,4] [,5]
[1,] 1 6 11 16 21
[2,] 2 0 12 17 0
[3,] 0 0 13 0 23
[4,] 0 9 14 0 0
[5,] 5 10 15 20 25
>
On Sun, Mar 2, 2008 at 7:11 AM, Diogo André Alagador
<mcnda839 at mncn.csic.es> wrote:
> To all,
>
>
>
> I am undergoing an analysis involving big matrices of about 30000x200 which
> I have to handle in a more efficient way. So I would like some advice to
> build such efficient function to deliver the following result:
>
>
>
> - starting with 2 matrices of the same dimension (eg. A and B)
>
>
>
> 0 0 3 5 6 0 0 5
>
> A= 0 0 6 4 B= 0 4 3 5
>
> 0 0 5 0 1 0 0 9
>
>
>
> - the function should deliver a C matrix (same dimension too),
> where at each position C(i,j), compares A and B.
>
> if A(i,j)=0, than C(i,j)=0,
>
> if A(i,j)!=0, than C(i,j)=B(i,j)
>
>
>
> 6 0 0 5
>
> C= 0 0 3 5
>
> 0 0 0 0
>
>
>
> Although not an expert I could build a function with 2 cycles (reading
> columns and rows) which is not quick. Maybe you can help me in this
> "challenge".
>
>
>
> Much thanks in advance,
>
>
>
>
> Diogo André Alagador
> Biodiversity & Global Change Lab, Museo Nacional de Ciencias Naturales,
> CSIC, Madrid, España
> Forest Research Centre, Instituto Superior de Agronomia, Universidade
> Técnica de Lisboa, Lisboa, Portugal
>
>
> [[alternative HTML version deleted]]
>
>
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> and provide commented, minimal, self-contained, reproducible code.
>
>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
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