[R] Switching entries in vector in by groups of two
Marc Schwartz
marc_schwartz at comcast.net
Fri Jun 27 16:31:05 CEST 2008
on 06/27/2008 09:17 AM Marc Schwartz wrote:
> on 06/27/2008 09:11 AM David Afshartous wrote:
>> All,
>>
>> I have a long vector that contains an even number of entries. I'd like to
>> switch the 1st and 2nd entry, the 3rd and 4th, and so on, without
>> writing a
>> loop.
>>
>> This code works:
>>
>> X = c(8, 10, 6, 3, 20, 1)
>> index = c(2,1,4,3,6,5)
>> X[index]
>>
>> But for a long list is there a way to generate the index? I can get the
>> parts to the index as:
>>
>> index.odd = seq(1,length(X), by = 2)
>> index.even = index.odd + 1
>>
>> Is there a simple way to interweave them to produce the desired
>> index? Or
>> is there a better way?
>>
>> Cheers,
>> David
>
> How about this:
>
> > as.vector(t(matrix(X, ncol = 2, byrow = TRUE)[, 2:1]))
> [1] 10 8 3 6 1 20
>
> Trying a longer vector as well:
>
> > Vec <- sample(20)
>
> > Vec
> [1] 13 20 14 10 12 7 3 19 11 15 1 4 9 18 6 8 5 16 17 2
>
> > as.vector(t(matrix(Vec, ncol = 2, byrow = TRUE)[, 2:1]))
> [1] 20 13 10 14 7 12 19 3 15 11 4 1 18 9 8 6 16 5 2 17
This can be shortened somewhat by flipping rows rather than columns:
> as.vector(matrix(Vec, nrow = 2)[2:1, ])
[1] 20 13 10 14 7 12 19 3 15 11 4 1 18 9 8 6 16 5 2 17
HTH,
Marc
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