# [R] Pairwise Partitioning of a Vector

Peter Dalgaard p.dalgaard at biostat.ku.dk
Mon Jun 23 08:40:10 CEST 2008

```Gundala Viswanath wrote:
> Hi,
>
> How can I partitioned an example vector like this
>
>
>> print(myvector)
>>
>  [1]   30.9   60.1   70.0   73.0   75.0   83.9   93.1   97.6   98.8  113.9
>
> into the following pairwise partition:
>
> PAIR1
> part1  = 30.9
> part2  = 60.1   70.0   73.0   75.0   83.9   93.1   97.6   98.8  113.9
>
> PAIR2
> part1 = 30.9   60.1
> part2 =  70.0   73.0   75.0   83.9   93.1   97.6   98.8  113.9
>
> ....
>
> PAIR9
> part1 = 30.9   60.1   70.0   73.0   75.0   83.9   93.1   97.6   98.8
> part2 = 113.9
>
>
> I'm stuck with this kind of loop:
>
Your code seems strangely out of sync with your example. Why does gexp
want to me a matrix and what is the sorting for??

lapply(1:9, function(n) {ix <- seq_len(n); list(part1=myvector[ix],
part2=myvector[-ix])})

?

> __BEGIN__
>
> # gexp is a Vector
>
> process_two_partition <- function(gexp) {
>     sort.gexp <- sort(as.matrix(gexp))
>     print(sort.gexp)
>
>     for (posb in 1:ncol(gexp)) {
>         for (pose in 1:ncol(gexp)) {
>
>           sp_b <- pose+1
>           sp_e <- ncol(gexp)
>
>           # This two doesn't do what I want
>           part1 <- sort.gexp[posb:pose]
>           part2 <- sort.gexp[sp_b:sp_e]
>
>          # we later want to process part1 and part2 separately
>
>         }
>     }
>
> }
>
> __END__
>
> - Gundala Viswanath
> Jakarta - Indonesia
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> and provide commented, minimal, self-contained, reproducible code.
>

--
O__  ---- Peter Dalgaard             Øster Farimagsgade 5, Entr.B
c/ /'_ --- Dept. of Biostatistics     PO Box 2099, 1014 Cph. K
(*) \(*) -- University of Copenhagen   Denmark      Ph:  (+45) 35327918
~~~~~~~~~~ - (p.dalgaard at biostat.ku.dk)              FAX: (+45) 35327907

```