# [R] Find missing days

Lauri.Nikkinen at veripalvelu.fi Lauri.Nikkinen at veripalvelu.fi
Wed Jan 2 09:07:21 CET 2008

```Thanks Gabor. Neat, it creates a df but this in not the solution I'm
looking for. This is hard to explain but I'll give it a try. See, in my
original df, in lev1, there is only 20 days

> range(df\$date1[df\$lev == "lev1"])
[1] "2007-09-01" "2007-09-23"

and we all know that in September there is 30 days. So, the missing days
in level df\$lev1 are

>    lev      date1
> 1  lev1 2007-09-03
> 2  lev1 2007-09-04
> 4  lev1 2007-09-24
> 5  lev1 2007-09-25
> 6  lev1 2007-09-26
> 7  lev1 2007-09-27
> 8  lev1 2007-09-28
> 9  lev1 2007-09-29
> 10 lev1 2007-09-30

And corresponding missing values in level lev2 are

> 11 lev2 2007-09-01
> 12 lev2 2007-09-02
> 13 lev2 2007-09-03
> 14 lev2 2007-09-04
> 15 lev2 2007-09-05
> 16 lev2 2007-09-06
> 17 lev2 2007-09-07
> 18 lev2 2007-09-08
> 19 lev2 2007-09-09
> 20 lev2 2007-09-10
> 21 lev2 2007-09-11
> 22 lev2 2007-09-12
> 23 lev2 2007-09-13
> 24 lev2 2007-09-14
> 25 lev2 2007-09-15
> 26 lev2 2007-09-16
> 27 lev2 2007-09-17
> 28 lev2 2007-09-18
> 29 lev2 2007-09-19
> 30 lev2 2007-09-20
> 31 lev2 2007-09-21
> 32 lev2 2007-09-22
> 33 lev2 2007-09-23
> 34 lev2 2007-10-17
> 35 lev2 2007-10-18
> 36 lev2 2007-10-19
> 37 lev2 2007-10-20
> 38 lev2 2007-10-21
> 39 lev2 2007-10-22
> 20 lev2 2007-10-23
> 41 lev2 2007-10-24
> 42 lev2 2007-10-25
> 43 lev2 2007-10-26
> 44 lev2 2007-10-27
> 45 lev2 2007-10-28
> 46 lev2 2007-10-29
> 47 lev2 2007-10-20
> 48 lev2 2007-10-31

because there is also days from October there.

Hope this makes my problem clear.

-Lauri

-----Original Message-----
From: Gabor Grothendieck [mailto:ggrothendieck at gmail.com]
Sent: 2. tammikuuta 2008 9:53
To: Nikkinen Lauri
Cc: r-help at stat.math.ethz.ch
Subject: Re: [R] Find missing days

Then just place it in a by like this.  The z<- line is from prior post:

do.call(rbind, by(df, df\$lev, function(df) {
z <- structure(setdiff(do.call(seq, as.list(range(df\$date1))),
df\$date1),
class = "Date")
if (length(z) > 0) data.frame(level = df\$lev[1], date = z)
}))

On Jan 2, 2008 2:38 AM,  <Lauri.Nikkinen at veripalvelu.fi> wrote:
date1
> range but my intention was to find missing days in each level (df\$lev)
> in corresponding month. The resulting df could look like this:
>
>    lev      date1
> 1  lev1 2007-09-03
> 2  lev1 2007-09-04
> 4  lev1 2007-09-24
> 5  lev1 2007-09-25
> 6  lev1 2007-09-26
> 7  lev1 2007-09-27
> 8  lev1 2007-09-28
> 9  lev1 2007-09-29
> 10 lev1 2007-09-30
> 11 lev2 2007-09-01
> 12 lev2 2007-09-02
> 13 lev2 2007-09-03
> 14 lev2 2007-09-04
> 15 lev2 2007-09-05
> 16 lev2 2007-09-06
> 17 lev2 2007-09-07
> 18 lev2 2007-09-08
> 19 lev2 2007-09-09
> 20 lev2 2007-09-10
> 21 lev2 2007-09-11
> 22 lev2 2007-09-12
> 23 lev2 2007-09-13
> 24 lev2 2007-09-14
> 25 lev2 2007-09-15
> 26 lev2 2007-09-16
> 27 lev2 2007-09-17
> 28 lev2 2007-09-18
> 29 lev2 2007-09-19
> 30 lev2 2007-09-20
> 31 lev2 2007-09-21
> 32 lev2 2007-09-22
> 33 lev2 2007-09-23
> 34 lev2 2007-10-17
> 35 lev2 2007-10-18
> 36 lev2 2007-10-19
> 37 lev2 2007-10-20
> 38 lev2 2007-10-21
> 39 lev2 2007-10-22
> 20 lev2 2007-10-23
> 41 lev2 2007-10-24
> 42 lev2 2007-10-25
> 43 lev2 2007-10-26
> 44 lev2 2007-10-27
> 45 lev2 2007-10-28
> 46 lev2 2007-10-29
> 47 lev2 2007-10-20
> 48 lev2 2007-10-31
> 49 lev3 2007-10-01
> etc.
>
> Thanks again,
> Lauri
>
>
> -----Original Message-----
> From: Gabor Grothendieck [mailto:ggrothendieck at gmail.com]
> Sent: 2. tammikuuta 2008 9:22
> To: Nikkinen Lauri
> Cc: r-help at stat.math.ethz.ch
> Subject: Re: [R] Find missing days
>
> Try this.  It creates a sequence of dates from the range of df\$date1
and
> then does a setdiff between that and the original dates.  The result
is
> numeric so we create a Date structure out of it.
>
> structure(setdiff(do.call(seq, as.list(range(df\$date1))), df\$date1),
> class = "Date")
>
>
> On Jan 2, 2008 1:55 AM,  <Lauri.Nikkinen at veripalvelu.fi> wrote:
> > Hi,
> >
> > I have a data.frame like this:
> >
> > y <- rnorm(60)
> > lev <- gl(3,20, labels=paste("lev", 1:3, sep=""))
> > date1 <- as.Date(seq(ISOdate(2007,9,1), ISOdate(2007,11,5),
> > by=60*60*24))
> > date1 <- date1[-c(3,4,15,34,38,40)]
> > df <- data.frame(lev=lev, date1=date1, y=y)
> >
> > I would like to produce a new data.frame with missing days in
df\$date1
> > in each df\$lev, like this:
> >
> >    lev      date1
> > 1  lev1 2007-09-03
> > 2  lev1 2007-09-04
> > 3  lev1 2007-09-15
> > 4  lev2 2007-09-01
> > 5  lev2 2007-09-02
> > etc.
> >
> > How can I do this?
> >
> > Thanks,
> > Lauri
> > FRCBS
> >
> >
> >
> >        [[alternative HTML version deleted]]
> >
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