[R] Find missing days

[Gabor Grothendieck]

Try this.  It creates a sequence of dates from the range of df$date1 and
then does a setdiff between that and the original dates.  The result is
numeric so we create a Date structure out of it.

structure(setdiff(do.call(seq, as.list(range(df$date1))), df$date1),
class = "Date")


On Jan 2, 2008 1:55 AM,  <Lauri.Nikkinen at veripalvelu.fi> wrote:
> Hi,
>
> I have a data.frame like this:
>
> y <- rnorm(60)
> lev <- gl(3,20, labels=paste("lev", 1:3, sep=""))
> date1 <- as.Date(seq(ISOdate(2007,9,1), ISOdate(2007,11,5),
> by=60*60*24))
> date1 <- date1[-c(3,4,15,34,38,40)]
> df <- data.frame(lev=lev, date1=date1, y=y)
>
> I would like to produce a new data.frame with missing days in df$date1
> in each df$lev, like this:
>
>    lev      date1
> 1  lev1 2007-09-03
> 2  lev1 2007-09-04
> 3  lev1 2007-09-15
> 4  lev2 2007-09-01
> 5  lev2 2007-09-02
> etc.
>
> How can I do this?
>
> Thanks,
> Lauri
> FRCBS
>
>
>
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