[R] counts of each column that are not NA, and/or greater than column means

Dimitris Rizopoulos Dimitris.Rizopoulos at med.kuleuven.be
Mon Feb 4 10:12:48 CET 2008


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check the following options:

test <- matrix(c(1,2,3,NA,2,3,NA,NA,2), 3, 3)

# A
colSums(!is.na(test))

# B
mat <- test > rep(colMeans(test, na.rm = TRUE), each = nrow(test))
colSums(!is.na(mat) & mat)

apply(test, 2, function(x) {
     mus <- mean(x, na.rm = TRUE)
     sum(x > mus, na.rm = TRUE)
})


I hope it helps.

Best,
Dimitris

----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven

Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
      http://www.student.kuleuven.be/~m0390867/dimitris.htm


Quoting Ng Stanley <stanleyngkl at gmail.com>:

> Hi,
>
> Given a test matrix, test <- matrix(c(1,2,3,NA,2,3,NA,NA,2), 3,3)
>
> A) How to compute the counts of each column (excluding the NA) i.e., 3, 2, 1
>
> B) How to compute the counts of each column (excluding the NA) that are
> greater than the column means ? i.e., 1, 1, 0
>
> I could write a for loop, but hope to use better alternative.
>
> 	[[alternative HTML version deleted]]
>
> ______________________________________________
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>
>



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