[R] adding rows as arithmatic calculation on original rows
Gabor Grothendieck
ggrothendieck at gmail.com
Fri Dec 5 23:50:42 CET 2008
Here is a solution using sqldf
library(sqldf)
DF2 <-
structure(list(myID = structure(1:4, .Label = c("a", "b", "c",
"d"), class = "factor"), myType = structure(c(2L, 2L, 1L, 1L), .Label
= c("Double",
"Single"), class = "factor"), myNum1 = c(10, 15, 22, 4), myNum2 = c(11,
25, 33, 6), myNum3 = c(12, 35, 44, 8)), .Names = c("myID", "myType",
"myNum1", "myNum2", "myNum3"), row.names = c(NA, -4L), class = "data.frame")
sqldf("select 1 TotalLevel, '+' myID, myType, avg(myNum1) myNum1,
avg(myNum2) myNum2, avg(myNum3) myNum3
from DF2
group by myType
union
select 0 TotalLevel, *
from DF2
order by myType, TotalLevel, myID",
method = "raw")[-1]
The output is (display in fixed font):
myID myType myNum1 myNum2 myNum3
1 c Double 22.0 33.0 44.0
2 d Double 4.0 6.0 8.0
3 + Double 13.0 19.5 26.0
4 a Single 10.0 11.0 12.0
5 b Single 15.0 25.0 35.0
6 + Single 12.5 18.0 23.5
On Fri, Dec 5, 2008 at 3:21 PM, Ferry <fmi.mlist at gmail.com> wrote:
> Dear R users,
>
> Suppose I have the following data.frame:
>
> myID myType myNum1 myNum2 myNum3
> a Single 10 11 12
> b Single 15 25 35
> c Double 22 33 44
> d Double 4 6 8
>
> and I want to have new records:
>
> myID myType myNum1 myNum2 myNum3
> e Single 12.5 18 23.5
> f Double 13 19.5 28
>
> where record e got its myNum1-3 as the average from record a and b, and
> record f got its myNum1-3 as the average from record c and d.
>
> and the final data.frame should be like the following:
>
> myID myType myNum1 myNum2 myNum3
> a Single 10 11 12
> b Single 15 25 35
> e Single 12.5 18 43.5
> c Double 22 33 44
> d Double 4 6 8
> f Double 13 19.5 28
>
> Any idea is appreciated. Thanks beforehand.
>
> Ferry
>
> [[alternative HTML version deleted]]
>
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