[R] Cartesian Product Of Character Vectors

[Rory.WINSTON at rbs.com]

Sorry, I spoke too soon...

interaction() only works for sequences of equal length. Anyone know a method that works with unequal-length vectors?


Rory Winston
RBS Global Banking & Markets
Office: +44 20 7085 4476

-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of WINSTON, Rory, GBM
Sent: 05 December 2008 14:20
To: dwinsemius at comcast.net
Cc: r-help at r-project.org
Subject: Re: [R] Cartesian Product Of Character Vectors

Hi David

Perfect - if I specify sep="", it gives me exactly what I need.

Cheers



Rory Winston
RBS Global Banking & Markets
Office: +44 20 7085 4476

-----Original Message-----
From: David Winsemius [mailto:dwinsemius at comcast.net]
Sent: 05 December 2008 14:16
To: WINSTON, Rory, GBM
Cc: r-help at r-project.org
Subject: Re: [R] Cartesian Product Of Character Vectors

Does this satisfy?

levels(interaction(x,y))
[1] "aaa.1" "bbb.1" "ccc.1" "aaa.2" "bbb.2" "ccc.2" "aaa.3" "bbb.3"
"ccc.3"

--
David Winsemius


On Dec 5, 2008, at 8:12 AM, <Rory.WINSTON at rbs.com> <Rory.WINSTON at rbs.com> wrote:

> Hi all
>
> (I'm sure this question has been asked before, but I cant find it).
>
> If I have two character vectors:
>
>> x <- c("aaa","bbb","ccc")
>> y <- c("1","2","3")
>
> How can I get the cartesian product of the string values?
>
>> expand.grid(x,y)
>
> Gives me a data frame with separate columns...however, I cant seem to
> get *apply to paste the column values together.
>
> Thanks
> Rory
>
> Rory Winston
> RBS Global Banking & Markets
> 280 Bishopsgate, London, EC2M 4RB
> Office: +44 20 7085 4476
>
>
>
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