[R] help with "persp" function

jim holtman jholtman at gmail.com
Sun Aug 31 02:44:55 CEST 2008


Is this what you want to do:

x <- seq(from=1,to=3,by=.1)
y <- seq(1,4,by=.1)
z <- matrix(1, length(x), length(y))
persp(x=x,y=y,z,zlim=c(0,2))


On Sat, Aug 30, 2008 at 2:08 PM, dxc13 <dxc13 at health.state.ny.us> wrote:
>
> Dear List,
>
> I am trying to draw a rectangular plane using the persp function, however I
> can't seem to get it to work. I want the length along x1 axis to be between
> 1 and 3 and the length along the x2 axis to be between 1 and 4.  All z
> values for x1 should be equal (say, z=1) because this is a plane, not a
> cube.  Below is my current code.  Any help is appreciated
> Thanks in advance
>
> dxc13
>
> x <- seq(from=1,to=3,by=.1)
> y <- seq(1,4,by=.1)
> f <- array(1,dim=c(21,1))
> z <- as.matrix(cbind(x,y,f))
> persp(x=x,y=y,z)
>
> --
> View this message in context: http://www.nabble.com/help-with-%22persp%22-function-tp19235739p19235739.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?



More information about the R-help mailing list