[R] Dealing with NaN's in data frames

[Muenchen, Robert A (Bob)]

Hi Jon,

Here's one way.

> x <- c(1,2,3,4,NaN)
> y <- c(1,2,NaN,4,5)
> 
> myDF <- data.frame(x,y)
> myDF
    x   y
1   1   1
2   2   2
3   3 NaN
4   4   4
5 NaN   5
> 
> myDF[ is.na(myDF) ] <- NA
> myDF
   x  y
1  1  1
2  2  2
3  3 NA
4  4  4
5 NA  5

Cheers,
Bob

=========================================================
Bob Muenchen (pronounced Min'-chen), Manager 
Statistical Consulting Center
U of TN Office of Information Technology
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FAX: (865) 974-4810
Email: muenchen at utk.edu
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=========================================================


> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
> project.org] On Behalf Of Peck, Jon
> Sent: Friday, August 15, 2008 10:28 PM
> To: r-help at r-project.org
> Subject: [R] Dealing with NaN's in data frames
> 
> I am looking for the most efficient way to replace all occurrences of
> NaN in a data frame with NA.  I can do this with a double loop, but it
> seems that there should be a higher level and more efficient way.
With
> is.na, I could use ifelse, but if.nan seems not to have similar
> capabilities.
> 
> 
> 
> TIA,
> 
> Jon Peck
> 
> 
> 
> Jon K. Peck
> 
> jkpeck at aya.yale.edu
> 
> 
> 
> 
> 	[[alternative HTML version deleted]]
> 
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