# [R] g(x,y) = f(x,y) - e(x)- e(y)?

Greg Snow Greg.Snow at imail.org
Wed Apr 23 18:52:56 CEST 2008

```It is not clear exactly what you want to do by subtracting a vector from a matrix, but look at the "sweep" function, it may do what you want.

--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.snow at imail.org
(801) 408-8111

> -----Original Message-----
> From: r-help-bounces at r-project.org
> [mailto:r-help-bounces at r-project.org] On Behalf Of William Simpson
> Sent: Wednesday, April 23, 2008 4:59 AM
> To: Philipp Pagel
> Cc: r-help at r-project.org
> Subject: Re: [R] g(x,y) = f(x,y) - e(x)- e(y)?
>
> Thanks Phipp very much for your help. I had meant, given that
> I'd computed the matrix f[x,y] and the vector e[x], how to
> take the difference. What is confusing is how to subtract a
> vector from a matrix. I don't want the recycling rule.
>
> Cheers
> Bill
>
> On Tue, Apr 22, 2008 at 9:53 AM, Philipp Pagel
> <p.pagel at wzw.tum.de> wrote:
> >
> >  > g(x,y) = f(x,y) - e(x)- e(y)
> >  > These are continuous functions. I am not sure how to do
> this with
> > the  > discrete equivalents in R.
> >
> >  Is this what you are looking for?
> >
> >  g <- function(x, y) {
> >
> >         f(x,y) - e(x) - e(y)
> >  }
> >
> >  cu
> >         Philipp
> >
> >  --
> >  Dr. Philipp Pagel
> >  Lehrstuhl für Genomorientierte Bioinformatik  Technische
> Universität
> > München  Wissenschaftszentrum Weihenstephan  85350
> Freising, Germany
> > http://mips.gsf.de/staff/pagel
> >
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> >  and provide commented, minimal, self-contained, reproducible code.
> >
>
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