Uwe Ligges ligges at statistik.uni-dortmund.de
Mon Oct 29 13:17:38 CET 2007

```You got at least two answers on this yesterday. If you want more precise

Uwe Ligges

osita k ezeh wrote:
> hello,
>
> please can anyone help me out. Am a new user of R
> program. Am having problem
> with this code below, not getting the expected
> results.
>
>  Each m, the cumulative sum should be 1.000 but the
> 2nd and 3rd m returned 2.000 and 3.000
>
>
>
> thanks
> Aruike
>
>
>
> pp=function(x,n,M){z=1.0;a=2.3071430;b=7.266064;H=3
>
>      out.h=c()
>
>      out.y=c()
>
>      out.m=c()
>
>      out.prob=c()
>
>
>
>        for(h in 1:H){
>
>        for(m in 1:M){
>
>        for(y in 0:m){
>
>
>
>
> g=lgamma(m+z)+lgamma(n[h]+a+b)+lgamma(x[h]+y+a)+lgamma(n[h]+m+b-x[h]-y)
>
>
>
> g=g-lgamma(y+z)-lgamma(m-y+z)-lgamma(x[h]+a)-lgamma(n[h]+b-x[h])-
> lgamma(n[h]+m+a+b)
>
>
>
>      out.h=c(out.h,h)
>
>      out.y=c(out.y,y)
>
>      out.m=c(out.m,m)
>
>      out.prob=c(out.prob, exp(g))
>
>    out.cum=c(cumsum(out.prob))
>
>
>
>  Result=data.frame(out.h,out.y,out.m,out.prob,out.cum)
>
>  }}}}
>
>  Kings=pp(x=c(19,20), n=c(52,60),3)
>
>  Kings
>
>    out.h out.y out.m   out.prob   out.cum
>
> 1      1     0     1 0.65395431 0.6539543
>
> 2      1     1     1 0.34604569 1.0000000
>
> 3      1     0     2 0.43127277 1.4312728
>
> 4      1     1     2 0.44536308 1.8766358
>
> 5      1     2     2 0.12336415 2.0000000
>
> 6      1     0     3 0.28672775 2.2867277
>
> 7      1     1     3 0.43363507 2.7203628
>
> 8      1     2     3 0.23440955 2.9547724
>
> 9      1     3     3 0.04522764 3.0000000
>
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