[R] formatting a list
jholtman at gmail.com
Sun Oct 21 19:34:18 CEST 2007
What is it that you want to do? The 'scan' statement give you a list
of length 7000 with 19 entries each. Do you want to create a matrix
that has 7000 rows by 19 columns? If so, then you just have to take
the output of the 'scan' and do:
x.matrix <- do.call('rbind', x) # gives 7000 x 19 matrix.
So I am still not sure exactly what your input is and what you want to
do with it.
On 10/21/07, Tomas Vaisar <tvaisar at u.washington.edu> wrote:
> Hi Jim,
> thanks a lot. It works, however - my other problem is that I need to
> transpose the original table before reading it into the list because the
> data come from Excel and it can't handle 7000 columns. I could read it
> in R transpose end write into a new tab delim file and then read it back
> in, but I would think that there might be a way in R to do both.
> Would you know about the way?
> jim holtman wrote:
> > another choice is:
> > x <- scan('temp.txt', what=c(rep(list(0), 19)))
> > On 10/20/07, Tomas Vaisar <tvaisar at u.washington.edu> wrote:
> >> Hi,
> >> I am new to R and need to read in a file with 19 columns and 7000 rows
> >> and make it into a list of 7000 lists with 19 items each. For a
> >> simpler case of 10 by 10 table I used x <-scan("file",
> >> list(0,0,0,0,0,0,0,0,0,0)), perhaps clumsy, but it did the job.
> >> However with the large 19x7000 (which needs to be transposed) I am not
> >> sure how to go about it.
> >> Coudl somebody suggest a way?
> >> Thanks,
> >> Tomas
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What is the problem you are trying to solve?
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