[R] formatting a list
jholtman at gmail.com
Sun Oct 21 01:51:40 CEST 2007
another choice is:
x <- scan('temp.txt', what=c(rep(list(0), 19)))
On 10/20/07, Tomas Vaisar <tvaisar at u.washington.edu> wrote:
> I am new to R and need to read in a file with 19 columns and 7000 rows
> and make it into a list of 7000 lists with 19 items each. For a
> simpler case of 10 by 10 table I used x <-scan("file",
> list(0,0,0,0,0,0,0,0,0,0)), perhaps clumsy, but it did the job.
> However with the large 19x7000 (which needs to be transposed) I am not
> sure how to go about it.
> Coudl somebody suggest a way?
> R-help at r-project.org mailing list
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
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What is the problem you are trying to solve?
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