[R] chi2
Alberto Monteiro
albmont at centroin.com.br
Wed Oct 10 13:50:38 CEST 2007
Elyakhlifi Mustapha wrote:
>
> I want to use the quantile function so I read the doc but I don't
> understand with this
>
> > qchisq(seq(0.05,0.95,by=0.05),df=(length(don)-1))
> [1] 62667.11 62795.62 62882.42 62951.47 63010.74 63064.00 63113.39
> 63160.27 63205.65 63250.33 63295.04 63340.48 63387.48 63437.03
> 63490.53 63550.14 63619.68 [18] 63707.24 63837.16
>
> Can you help me please?
>
Notice that, if you want adequate help, you must provide
all information. You didn't give don, so we can't reproduce
the output.
However, since qchisq(0.5, df) for large df is very close to df,
it's possible to infer that length(don)-1 = 63251.
If you plot dchisq(x, df=63251) (for example:
x <- ((-1000):1000) + 63251
plot(x, dchisq(x, df=63251), type="l")
or
y <- rchisq(10000, df=63251)
hist(y)
or any other way to view the probability density function),
it's easy so see that chi2 for large n is normal-like, with
mean close to df, and standard deviation close to sqrt(df).
Alberto Monteiro
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