[R] The "reverse" of do.call("rbind",) on a list

[Christos Hatzis]

Try split:

> x <- matrix(letters[1:4], 2)
> x
     [,1] [,2]
[1,] "a"  "c" 
[2,] "b"  "d" 

> split(x, row(x))
$`1`
[1] "a" "c"

$`2`
[1] "b" "d"
 
-Christos

> -----Original Message-----
> From: r-help-bounces at r-project.org 
> [mailto:r-help-bounces at r-project.org] On Behalf Of Søren Højsgaard
> Sent: Monday, November 12, 2007 8:08 PM
> To: r-help at stat.math.ethz.ch
> Subject: [R] The "reverse" of do.call("rbind",) on a list
> 
> Dear List,
> I want to turn the matrix
> > xm
>      [,1] [,2]
> [1,] "a"  "b" 
> [2,] "d"  "e" 
> 
> into a list "by rows" as:
> [[1]]
> [1] "a" "b"
> [[2]]
> [1] "d" "e"
> 
> A (bad?) way of doing this is as
> > unlist(apply(xm,1, list), recursive=F)
> [[1]]
> [1] "a" "b"
> [[2]]
> [1] "d" "e"
>  
> - but there must be a more elegant way. Can anyone help on 
> this? Thanks!
> Søren
>  
> 
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