[R] duplicate rows in a matrix
Bill.Venables at csiro.au
Bill.Venables at csiro.au
Sat Nov 3 05:21:41 CET 2007
... but you may not want the rows re-ordered. Here is a possible
modification that uses a similar idea:
m <- matrix(1:(2*nrow(A)), ncol = 2, byrow = TRUE)
AA <- rbind(A, A)[order(m), ]
Bill Venables
-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org]
On Behalf Of Juan Manuel Barreneche
Sent: Saturday, 3 November 2007 2:34 AM
To: Silvia Lipski; r-help list
Subject: Re: [R] duplicate rows in a matrix
My sugestion (for an alphabetically ordered output)
AA <- rbind(A,A)
AA <- AA[order(AA[,1]), ] ## so your matrix gets alphabetically ordered
JM
On Fri, 2007-11-02 at 09:04 -0700, Silvia Lipski wrote:
> Hi!
>
> Is there a fast way to duplicate rows in a matrix?
> I would like to do the following:
>
> change a matrix A like:
> [,1] [,2]
> [1,] Kevin 1
> [2,] Alf 2
>
> into :
> [,1] [,2]
> [1,] Kevin 1
> [2,] Kevin 1
> [3,] Alf 2
> [4,] Alf 2
>
> i.e. double all rows. The only way I could think off
> was: rbind(A[1,],A[1,],A[2,],A[2,]) - which is really
> impractible, of course.
>
> Can anyone help, please?
> Thank you,
> Silvia
>
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