[R] Percentage area of a distribution

[Alan Gibson]

let me amend my previous message to remove a silly mistake:

I have a (non-normal) distribution S that is a mixture of two normal
distributions C and C-bar. I need to find the percentage of the area
of S that both C and C-bar occupy.

Thanks again,
Alan Gibson

On 5/1/07, Leeds, Mark (IED) <Mark.Leeds at morganstanley.com> wrote:
> What do you mean by a normal distribution made up of to normal
> distributions ? A mixture of two
> Normals with different variances doesn't result in a normal distribution
> so I'm not sure what you
> Nean but maybe someone else does. No offense intended but, if noone
> replies,
> That means that noone else understood either.
>
>
> -----Original Message-----
> From: r-help-bounces at stat.math.ethz.ch
> [mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of Alan Gibson
> Sent: Tuesday, May 01, 2007 8:02 PM
> To: R-help at stat.math.ethz.ch
> Subject: [R] Percentage area of a distribution
>
> It seems like this should be pretty straight forward, but for some
> reason the answer escapes me.
>
> I have a normal distribution S made up of two normal distributions C and
> C-bar. I need to find the percentage of the area of S that both C and
> C-bar occupy.
>
> Any suggestions?
>
> Thanks in advance,
> Alan Gibson
>
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