[R] binned column in a data.frame

[jim holtman]

You can also use 'cut' to break the bins:

> x <- c(1,2,6,8,13,0,5,10, runif(10) * 100)
> x.bins <- seq(0, max(x)+5, 5)
> x.cut <- cut(x, breaks=x.bins, include.lowest=TRUE)
> x.names <- paste(head(x.bins, -1), tail(x.bins, -1), sep='-')
> data.frame(x, bins=x.names[x.cut])
          x  bins
1   1.00000   0-5
2   2.00000   0-5
3   6.00000  5-10
4   8.00000  5-10
5  13.00000 10-15
6   0.00000   0-5
7   5.00000   0-5
8  10.00000  5-10
9  75.85256 75-80
10 38.20424 35-40
11 77.30647 75-80
12 62.02278 60-65
13 73.42095 70-75
14 78.69244 75-80
15 66.52972 65-70
16 61.64897 60-65
17 23.99252 20-25
18 42.08632 40-45


On 7/20/07, João Fadista <Joao.Fadista at agrsci.dk> wrote:
> Dear all,
>
> I would like to know how can I create a binned column in a data.frame. The output that I would like is something like this:
>
> Start  Binned_Start
> 1        0-5
> 2        0-5
> 6        5-10
> 8        5-10
> 13      10-15
> ...
>
>
>
>
> Best regards
>
> João Fadista
> Ph.d. student
>
>
>
>         UNIVERSITY OF AARHUS
> Faculty of Agricultural Sciences
> Dept. of Genetics and Biotechnology
> Blichers Allé 20, P.O. BOX 50
> DK-8830 Tjele
>
> Phone:   +45 8999 1900
> Direct:  +45 8999 1900
> E-mail:  Joao.Fadista at agrsci.dk <mailto:Joao.Fadista at agrsci.dk>
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-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

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