[R] Using tapply to create a new table
Kalish, Josh
josh.kalish at credit-suisse.com
Fri Jan 26 19:21:18 CET 2007
Marc,
Thanks for pointing out the merge function. That gets me part of the way there. The only thing is that I can't get the tapply() results into a format that merge() will take. For example:
merge( set1 , tapply( set2$f1 , set2$commonField, mean ) , by="commonField" )
Gives me "Error in names... Unused arguments..."
I'm not sure what the result of a tapply() exactly is, but it doesn't seem to be a table.
Yeah, rank amateur questions...
Thanks,
Josh
-----Original Message-----
From: Marc Schwartz [mailto:marc_schwartz at comcast.net]
Sent: Friday, January 26, 2007 1:08 PM
To: Kalish, Josh
Cc: 'r-help at stat.math.ethz.ch'
Subject: Re: [R] Using tapply to create a new table
On Fri, 2007-01-26 at 12:39 -0500, Kalish, Josh wrote:
> All,
>
> I'm sure that this is covered somewhere, but I can't seem to find a
> good explanation. I have an existing table that contains information
> grouped by date. This is as so:
>
> Day NumberOfCustomers NumberOfComplaints
> 20060512 10040 40
> 20060513 32420 11
> ...
>
>
> I also have a table at the detail level as so:
>
> Day Meal PricePaid UsedCupon
> 20060512 Fish 14 Y
> 20060512 Chicken 20 N
> ...
>
> Is there a simple way to create summaries on the detail table and then
> join them into the first table above so that it looks like this:
>
> Day NumberOfCustomers NumberOfComplaints AveragePricePaid
> NumberUsingCupon
>
>
> I can do a tapply to get what I want from the detail table, but I
> can't figure out how to turn that into a table and join it back in.
>
>
>
> Thanks,
>
> Josh
Skipping the steps of using tapply() or aggregate() to get the summarized data from the second data frame, you would then use merge() to perform a SQL-like 'join' operation:
> DF.1
Day NumberOfCustomers NumberOfComplaints
1 20060512 10040 40
2 20060513 32420 11
> DF.2
Day Meal PricePaid UsedCupon
1 20060512 Fish 14 Y
2 20060512 Chicken 20 N
> merge(DF.1, DF.2, by = "Day")
Day NumberOfCustomers NumberOfComplaints Meal PricePaid
1 20060512 10040 40 Fish 14
2 20060512 10040 40 Chicken 20
UsedCupon
1 Y
2 N
By default, only rows matching on the 'by' argument in both data frames will be in the result. See the 'all.x' and 'all.y' arguments to handle other scenarios of including non-matching rows.
See ?merge, which BTW:
help.search("join")
would point you to, if you are familiar with the term from relational data base operations.
HTH,
Marc Schwartz
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