[R] simple q: returning a logical vector of substring matches
ggrothendieck at gmail.com
Sat Jan 20 20:32:18 CET 2007
Using the builtin month.abb try this:
regexpr("ov", month.abb) > 0
Although not needed here, if "ov" were a character string that could have
special characters such as . and * that have special meaning in a regular
expression then do this to prevent such interpretation:
regexpr("ov", month.abb, fixed = TRUE) > 0
On 1/20/07, lindeman at bard.edu <lindeman at bard.edu> wrote:
> I'm a relative R novice, and sometimes the simple things trip me up.
> Suppose I have
> a <- c("apple", "pear")
> and I want a logical vector of whether each of these strings contains
> "ear" (in this case, F T). What is the idiom?
> Mark Lindeman
> R-help at stat.math.ethz.ch mailing list
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
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