[R] memory problem --- use sparse matrices
Martin Maechler
maechler at stat.math.ethz.ch
Mon Jan 8 19:18:26 CET 2007
>>>>> "UweL" == Uwe Ligges <ligges at statistik.uni-dortmund.de>
>>>>> on Sun, 07 Jan 2007 09:42:08 +0100 writes:
UweL> Zoltan Kmetty wrote:
>> Hi!
>>
>> I had some memory problem with R - hope somebody could
>> tell me a solution.
>>
>> I work with very large datasets, but R cannot allocate
>> enough memoty to handle these datasets.
>>
>> I want work a matrix with row= 100 000 000 and column=10
>>
>> A know this is 1 milliard cases, but i thought R could
>> handle it (other commercial software like spss could do),
>> but R wrote out everytime: not enough memory..
>>
>> any good idea?
UweL> Buy a machine that has at least 8Gb (better 16Gb) of
UweL> RAM and proceed ...
Well, I doubt that Zoltan wants to *fill* his matrix with all
non-zeros. If he does, Uwe and Roger are right.
Otherwise, working with a *sparse* matrix, using the 'Matrix'
(my recommendation, but I am biased) or 'SparseM' package, might
well be feasible:
install.packages("Matrix") # if needed; only once for your R
library(Matrix) # each time you need it
TsparseMatrix <- function(nrow, ncol, i,j,x)
{
## Purpose: User friendly construction of sparse "Matrix" from triple
## ----------------------------------------------------------------------
## Arguments: (i,j,x): 2 integer and 1 numeric vector of the same length:
##
## The matrix M will have
## M[i[k], j[k]] == x[k] , for k = 1,2,..., length(i)
## and M[ i', j' ] == 0 for `` all other pairs (i',j')
## ----------------------------------------------------------------------
## Author: Martin Maechler, Date: 8 Jan 2007, 18:46
nnz <- length(i)
stopifnot(length(j) == nnz, length(x) == nnz,
is.numeric(x), is.numeric(i), is.numeric(j))
dim <- c(as.integer(nrow), as.integer(ncol))
## The conformability of (i,j) with 'dim' will be checked automatically
## by an internal "validObject()" that is part of new(.):
new("dgTMatrix", x = x, Dim = dim,
## our "Tsparse" Matrices use 0-based indices :
i = as.integer(i - 1:1),
j = as.integer(j - 1:1))
}
For example :
> TsparseMatrix(10,20, c(1,3:8), c(2,9,6:10), 7 * (1:7))
10 x 20 sparse Matrix of class "dgTMatrix"
[1,] . 7 . . . . . . . . . . . . . . . . . .
[2,] . . . . . . . . . . . . . . . . . . . .
[3,] . . . . . . . . 14 . . . . . . . . . . .
[4,] . . . . . 21 . . . . . . . . . . . . . .
[5,] . . . . . . 28 . . . . . . . . . . . . .
[6,] . . . . . . . 35 . . . . . . . . . . . .
[7,] . . . . . . . . 42 . . . . . . . . . . .
[8,] . . . . . . . . . 49 . . . . . . . . . .
[9,] . . . . . . . . . . . . . . . . . . . .
[10,] . . . . . . . . . . . . . . . . . . . .
But
nr <- 1e8
nc <- 10
set.seed(1)
i <- sample(nr, 10000)
j <- sample(nc, 10000)
x <- round(rnorm(10000), 2)
M <- TsparseMatrix(nr, nc, i=i, j=j, x=x)
works,
e.g. you can
x <- 1:10
system.time(y <- M %*% x) # needs around 4 sec on one of our better machines
y <- as.vector(y)
## but you can become even more efficient, translating from the
## so-called "triplet" to the (recommended) "Csparse"
## representation:
M. <- as(M, "CsparseMatrix")
object.size(M) / object.size(M.)
## 1.328921; i.e. we saved 33%
## and
system.time(y. <- M. %*% x) # much faster (1 sec)
identical(as.vector(y.), y)
--- --- ---
I hope this is useful to you.
Martin Maechler,
ETH Zurich
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