[R] Scatterplot3d model reporting question
John Fox
jfox at mcmaster.ca
Tue Dec 18 21:04:30 CET 2007
Dear Max,
I'm guessing that you're actually using scatter3d() in the Rcmdr package rather than scatterplot3d(), since the latter, I believe, doesn't fit regression surfaces.
If I'm right, then as it says in ?scatter3d, the smooth surface is fit by the gam() function in the mgcv package using a smoothing spline and there is no explicit equation to examine. See ?gam for more information.
I hope this helps,
John
--------------------------------
John Fox, Professor
Department of Sociology
McMaster University
Hamilton, Ontario, Canada L8S 4M4
905-525-9140x23604
http://socserv.mcmaster.ca/jfox
> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
> project.org] On Behalf Of Max
> Sent: December-18-07 2:02 PM
> To: r-help at stat.math.ethz.ch
> Subject: [R] Scatterplot3d model reporting question
>
> I've used the scatterplot3d function to graph some data and had it
> graph a "smooth" fit. Is there a way to actualy find out the function
> of the surface? I've looked through the help and figured out how to get
> it to report the following:
>
> Family: gaussian
> Link function: identity
>
> Formula:
> y ~ s(x, z)
>
> Parametric coefficients:
> Estimate Std. Error t value Pr(>|t|)
> (Intercept) 0.20750 0.01223 16.97 <2e-16 ***
> ---
> Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
>
> Approximate significance of smooth terms:
> edf Est.rank F p-value
> s(x,z) 8.403 17 9.729 1.76e-14 ***
> ---
> Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
>
> R-sq.(adj) = 0.684 Deviance explained = 70.9%
> GCV score = 0.017692 Scale est. = 0.016151 n = 108
>
> But I'm still not really sure what I'm looking at, either that or
> "smooth" means something different than I thought. Any help would be
> great!
>
> thanks,
>
> -Max
>
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