[R] Forcing coefficients in lm object
Prof Brian Ripley
ripley at stats.ox.ac.uk
Tue Aug 28 19:03:23 CEST 2007
It is fit$coefficients, not fit$coef .
>From the help page:
name: A literal character string or a name (possibly backtick
quoted). For extraction, this is normally (see under
Environments) partially matched to the 'names' of the object.
Note the qualifier 'for extraction', so you assigned a new element with
name 'coef', and predict.lm used fit$coefficients.
On Tue, 28 Aug 2007, J.J.P.Lebrec at lumc.nl wrote:
> Dear all,
>
> I would like to use predict.lm() with an existing lm object but with new arbitrary coefficients. I modify 'fit$coef' (see example below) "by hand" but the actual model in 'fit' used for prediction does not seem to be altered (although fit$coef is!).
>
> Can anyone please help me do this properly?
>
> Thanks in advance,
>
> Jérémie
>
>
>
>> dat <- data.frame(y=c(0,25,32,15), x=as.factor(c(1,1,2,2)))
>> fit <- lm(y ~ x, data=dat)
>> fit
>
> Call:
> lm(formula = y ~ x, data = dat)
>
> Coefficients:
> (Intercept) x2
> 12.5 11.0
>
>> fit$coef[[2]] <- 100
>> dat.new <- data.frame(x=as.factor(c(1,2,1,2)))
>> predict.lm(fit, dat.new)
> 1 2 3 4
> 12.5 23.5 12.5 23.5
>> fit
>
> Call:
> lm(formula = y ~ x, data = dat)
>
> Coefficients:
> (Intercept) x2
> 12.5 11.0
>
>> fit$coef
> (Intercept) x2
> 12.5 100.0
>>
>
>
>
> Jérémie Lebrec
> Dept. of Medical Statistics and Bioinformatics
> Leiden University Medical Center
> Postzone S-05-P
> P.O. Box 9600
> 2300 RC Leiden
> The Netherlands
> j.j.p.lebrec at lumc.nl
>
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>
--
Brian D. Ripley, ripley at stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UK Fax: +44 1865 272595
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