[R] how to collapse a list of 1 column matrix to a matrix?
adschai at optonline.net
adschai at optonline.net
Mon Aug 20 04:25:14 CEST 2007
One more question. After I collapse everything into one matrix, I would like to find the index of column that holds minimum value for each row. I remember that there is a function like maxCols but I can't seem to find the same thing for minimum value. Any suggestion please?
- adschai
----- Original Message -----From: Gabor Grothendieck Date: Sunday, August 19, 2007 8:48 pmSubject: Re: [R] how to collapse a list of 1 column matrix to a matrix?To: "adschai at optonline.net" Cc: r-help at stat.math.ethz.ch> Try this:> > L <- list(`1` = matrix(1:4, 4), `2` = matrix(5:8, 4))> sapply(L, c)> > Note that the list component names are kept as column names in > the result> > > On 8/19/07, adschai at optonline.net wrote:> > Hi,> >> > I encounter a situation where I have a list whose element is a > column matrix. Says,> >> > $'1'> > [,1]> > 1> > 2> > 3> >> > $'2'> > [,1]> > 4> > 5> > 6> >> > Is there fast way to collapse the list into a matrix like a > cbind operation in this case? Meaning, the result should be a > matrix that looks like:> >> > [,1] [,2]> > [1,] 1 4> > [2,] 2 5> > [3,] 3 6> >> > I can loop through all elements and do cbind manually. But I > think there must be a simpler way that I don't know. Thank you.> >> > - adschai> >> > ______________________________________________> > R-help at stat.math.ethz.ch mailing list> > https://stat.ethz.ch/mailman/listinfo/r-help> > PLEASE do read the posting guide http://www.R-> project.org/posting-guide.html> > and provide commented, minimal, self-contained, reproducible code.> >>
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