[R] question regarding is.factor()
Prof Brian Ripley
ripley at stats.ox.ac.uk
Mon Aug 13 13:21:31 CEST 2007
typeof() for 'types'.
However, "factor" is not a type but a class, so class() is probably what
you want.
On Mon, 13 Aug 2007, Jabez Wilson wrote:
> Dear all, please help with what must be a straightforward question which
> I can't answer.
But 'An Introduction to R' could.
> I add a column of my dataframe as factor of an existing column e.g.
>
> df[,5] <- factor(df[,2])
>
> and can test that it is by is.factor()
>
> but if I did not know in advance what "types" the columns were, is
> there a function to tell me what they are.
>
> i.e. instead of is.factor(), is.matrix(), is.list(), a function more
> like what.is()
>
>
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--
Brian D. Ripley, ripley at stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
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