[R] how to convert decimal date to its equivalent date format(YYYY.mm.dd.hr.min.sec)

[jim holtman]

Is this what you want?

> x <- scan(textConnection("1979.000000
+
+ 1979.020833
+
+ 1979.041667
+
+ 1979.062500"), what=0)
Read 4 items
> # get the year and then determine the number of seconds in the year so you can
> # use the decimal part of the year
> x.year <- floor(x)
> # fraction of the year
> x.frac <- x - x.year
> # number of seconds in each year
> x.sec.yr <- unclass(ISOdate(x.year+1,1,1,0,0,0)) - unclass(ISOdate(x.year,1,1,0,0,0))
> # now get the actual time
> x.actual <- ISOdate(x.year,1,1,0,0,0) + x.frac * x.sec.yr
>
> x.actual
[1] "1979-01-01 00:00:00 GMT" "1979-01-08 14:29:49 GMT" "1979-01-16
05:00:10 GMT"
[4] "1979-01-23 19:30:00 GMT"
>


On 8/7/07, Yogesh Tiwari <yogesh.mpi at googlemail.com> wrote:
> Hello R Users,
>
> How to convert decimal date to date as YYYY.mm.dd.hr.min.sec
>
> For example, I have decimal date in one column , and want to convert and
> write it in equivalent date(YYYY.mm.dd.hr.min.sec) in another next six
> columns.
>
> 1979.000000
>
> 1979.020833
>
> 1979.041667
>
> 1979.062500
>
>
>
> Is it possible in R ?
>
> Kindly help,
>
> Regards,
>
> Yogesh
>
>
>
>
>
> --
> Dr. Yogesh K. Tiwari,
> Scientist,
> Indian Institute of Tropical Meteorology,
> Homi Bhabha Road,
> Pashan,
> Pune-411008
> INDIA
>
> Phone: 0091-99 2273 9513 (Cell)
>         : 0091-20-258 93 600 (O) (Ext.250)
> Fax    : 0091-20-258 93 825
>
>        [[alternative HTML version deleted]]
>
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>


-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

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