[R] do.call vs. lapply for lists

[Gabor Grothendieck]

Consider this.  If L is a list with n components then

- do.call(f, L) calls f once
- lapply(L, f) calls f n times


On 4/9/07, Muenchen, Robert A (Bob) <muenchen at utk.edu> wrote:
> Hi All,
>
> I'm trying to understand the difference between do.call and lapply for
> applying a function to a list. Below is one of the variations of
> programs (by Marc Schwartz) discussed here recently to select the first
> and last n observations per group.
>
> I've looked in several books, the R FAQ and searched the archives, but I
> can't find enough to figure out why lapply doesn't do what do.call does
> in this case. The help files & newsletter descriptions of do.call sound
> like it would do the same thing, but I'm sure that's due to my lack of
> understanding about their specific terminology. I would appreciate it if
> you could take a moment to enlighten me.
>
> Thanks,
> Bob
>
> mydata <- data.frame(
>  id      = c('001','001','001','002','003','003'),
>  math    = c(80,75,70,65,65,70),
>  reading = c(65,70,88,NA,90,NA)
> )
> mydata
>
> mylast <- lapply( split(mydata,mydata$id), tail, n=1)
> mylast
> class(mylast) #It's a list, so lapply will so *something* with it.
>
> #This gets the desired result:
> do.call("rbind", mylast)
>
> #This doesn't do the same thing, which confuses me:
> lapply(mylast,rbind)
>
> #...and data.frame won't fix it as I've seen it do in other
> circumstances:
> data.frame( lapply(mylast,rbind) )
>
> =========================================================
>  Bob Muenchen (pronounced Min'-chen), Manager
>  Statistical Consulting Center
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