[R] apply for list or list -> array
Roger Bivand
Roger.Bivand at nhh.no
Tue Sep 19 10:37:56 CEST 2006
On Mon, 18 Sep 2006, Ahn ChaeHyung wrote:
> Dear all,
>
> I have the following list, "aa", composed of two 3*3 tables. I would like
> to use "apply" function to summarize it, but "apply" cannot handle "list".
> I want to do it without using any interation.
>
> 1. Is there any function like "apply" for list?
?lapply, ?sapply
> 2. Is there any way to transform that "list" to a 2*3*3 "array"?
>
Among other possibilities:
library(abind)
aa <- list(m1=matrix(rnorm(9), 3, 3), m2=matrix(runif(9), 3, 3))
a1 <- abind(aa, along=3)
str(a1)
dim(a1)
> thanks
>
> cahn
>
> -----------------------------------------
> >aa
> [[1]]
> [,1] [,2] [,3]
> [1,] 1 3 1
> [2,] 2 0 1
> [3,] 1 1 0
>
> [[2]]
> [,1] [,2] [,3]
> [1,] 1 3 1
> [2,] 2 0 1
> [3,] 1 1 0
>
>
> I would like to avoid any iteration
>
>
>
> -------------------------------------------------
> Ahn, Chaehyung (cahn) Ph.D.
> Alpha-Gamma Technologies Inc.
> My Home: http://blog.naver.com/cahn88
>
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>
--
Roger Bivand
Economic Geography Section, Department of Economics, Norwegian School of
Economics and Business Administration, Helleveien 30, N-5045 Bergen,
Norway. voice: +47 55 95 93 55; fax +47 55 95 95 43
e-mail: Roger.Bivand at nhh.no
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