[R] coerce matrix to number

[Jacques VESLOT]

if only 2 letters:
(z=="v")*1
else:
lapply(z, function(x) as.numeric(as.character(factor(x,levels= c("d","v","w"),labels=c(0,1,2)))))
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Jacques VESLOT

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Simone Gabbriellini a écrit :
> Dear List,
> 
> how can I coerce a matrix like this
> 
>       [,1] [,2] [,3] [,4] [,5] [,6]
> [1,] "0"  "1"  "1"  "0"  "0"  "0"
> [2,] "1"  "0"  "1"  "0"  "0"  "0"
> [3,] "1"  "1"  "0"  "0"  "0"  "0"
> [4,] "0"  "0"  "0"  "0"  "1"  "0"
> [5,] "0"  "0"  "0"  "1"  "0"  "0"
> [6,] "0"  "0"  "0"  "0"  "0"  "0"
> 
> to be filled with numbers?
> 
> this is the result of replacing some character ("v", "d") with 0 and  
> 1, using the code I found with RSiteSearch()
> 
> z[] <- lapply(z, factor, levels = c("d", "v"), labels = c(0, 1));
> 
> thank you,
> Simone
> 
> |-------------------------------------------------|
> 
> dott. Simone Gabbriellini
> PhD Student
> Dipartimento di Scienze Sociali
> Università di Pisa
> via Colombo 35 - 56100 Pisa
> mail: simone.gabbriellini at sp.unipi.it
> mobile: +39 3475710037
> 
> |-------------------------------------------------|
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