# [R] problem with putting objects in list

Rainer M Krug rkrug at sun.ac.za
Fri Sep 8 10:07:49 CEST 2006

Thanks a lot Tony

this explains a lot.
before. I would suggest to add it to the FAQs.

Rainer

Tony Plate wrote:
> I suspect you are not thinking about the list and the
> subsetting/extraction operators in the right way.
>
> A list contains a number of components.
>
> To get a subset of the list, use the '[' operator.  The subset can
> contain zero or more components of the list, and it is a list itself.
> So, if x is a list, then x[2] is a list containing a single component.
>
> To extract a component from the list, use the '[[' operator.  You can
> only extract one component at a time.  If you supply a vector index with
> more than one element, it will index recursively.
>
>> x <- list(1,2:3,letters[1:3])
>> x
> [[1]]
> [1] 1
>
> [[2]]
> [1] 2 3
>
> [[3]]
> [1] "a" "b" "c"
>
>> # a subset of the list
>> x[2:3]
> [[1]]
> [1] 2 3
>
> [[2]]
> [1] "a" "b" "c"
>
>> # a list with one component:
>> x[2]
> [[1]]
> [1] 2 3
>
>> # the second component itself
>> x[[2]]
> [1] 2 3
>> # recursive indexing
>> x[[c(2,1)]]
> [1] 2
>> x[[c(3,2)]]
> [1] "b"
>>
>
> Rainer M Krug wrote:
>> Hi
>>
>> I use the following code and it stores the results of density() in the
>> list dr:
>>
>> dens <- function(run) { density( positions\$X[positions\$run==run], bw=3,
>> cut=-2 ) }
>> dr <- lapply(1:5, dens)
>>
>> but the results are stored in dr[[i]] and not dr[i], i.e. plot(dr[[1]])
>> works, but plot([1]) doesn't.
>>
>> Is there any way that I can store them in dr[i]?
>>
>> Thanks a lot,
>>
>> Rainer
>>
>>
>>
>

--
Rainer M. Krug, Dipl. Phys. (Germany), MSc Conservation
Biology (UCT)

Department of Conservation Ecology and Entomology
University of Stellenbosch
Matieland 7602
South Africa

Tel:		+27 - (0)72 808 2975 (w)
Fax:		+27 - (0)21 808 3304
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email:	RKrug at sun.ac.za
Rainer at krugs.de