[R] Merge list to list - as list

[Gabor Grothendieck]

If z is the result then z[[i]] is formed from x[[i]] and y[[i]] using
the previous solution, viz.

z <- list()
z[[1]] <- mapply(cbind, x[[1]], y[[1]], SIMPLIFY = FALSE)
z[[2]] <- mapply(cbind, x[[2]], y[[2]], SIMPLIFY = FALSE)

or with a for loop (which is similar to the code you posted below except
the extraneous j loop is removed since its already incorporated
in the mapply):

z <- list()
for(i in seq(along = x))
   z[[i]] <- mapply(cbind, x[[1]], y[[1]], SIMPLIFY = FALSE)

or reducing the loop to a lapply:

lapply(seq(along = x), function(i) mapply(cbind, x[[i]], y[[i]],
SIMPLIFY = FALSE))



On 9/3/06, Muhammad Subianto <msubianto at gmail.com> wrote:
> Dear all,
> #Last week, I asked about merge x and y as list.
> #Now I have a dataset with list of list like:
> x <- list(list(matrix(1:20, 5, 4),matrix(1:20, 5, 4)),
>          list(matrix(1:20, 5, 4),matrix(1:20, 5, 4)))
> y <- list(list(c(1, -1, -1, 1, 1),c(1, 1, -1, -1, -1)),
>          list(c(1, 1, 1, 1, 1),c(1, 1, -1, 1, -1)))
> x
> y
>
> #I need merge x and y, I have tried with
> list.uni <- vector("list", length(x))
> for (i in 1:length(x)) {
>     for (j in 1:length(x[[1]])) {
>          list.uni[[i]][[j]] <- mapply(cbind,
>                                       x[[i]][[j]],
>                                       y[[i]][[j]],
>                                       SIMPLIFY=FALSE)
>     }
> }
> list.uni
>
> I have learn about ?lapply, ?sapply and ?mapply but I still didn't
> understand how to use it.
> I need the result something like
>
>
> [[1]]
> [[1]][[1]]
>     [,1] [,2] [,3] [,4] [5]
> [1,]    1    6   11   16  1
> [2,]    2    7   12   17  -1
> [3,]    3    8   13   18  -1
> [4,]    4    9   14   19  1
> [5,]    5   10   15   20  1
>
> [[1]][[2]]
>     [,1] [,2] [,3] [,4] [5]
> [1,]    1    6   11   16  1
> [2,]    2    7   12   17  1
> [3,]    3    8   13   18  -1
> [4,]    4    9   14   19  -1
> [5,]    5   10   15   20  -1
>
>
> [[2]]
> [[2]][[1]]
>     [,1] [,2] [,3] [,4] [5]
> [1,]    1    6   11   16  1
> [2,]    2    7   12   17  1
> [3,]    3    8   13   18  1
> [4,]    4    9   14   19  1
> [5,]    5   10   15   20  1
>
> [[2]][[2]]
>     [,1] [,2] [,3] [,4] [5]
> [1,]    1    6   11   16  1
> [2,]    2    7   12   17  1
> [3,]    3    8   13   18  -1
> [4,]    4    9   14   19  1
> [5,]    5   10   15   20  -1
>
> Thanks you for any help.
> Best wishes, Muhammad Subianto
>
>
>
>
> #Gabor Grothendieck ggrothendieck at gmail.com
> #Mon Aug 28 13:53:52 CEST 2006
>
> Here are two ways:
>
> 1. use indexes:
>
> lapply(seq(along = x), function(i) cbind(x[[i]], y[[i]]))
>
> 2. use mapply:
>
> mapply(cbind, x, y, SIMPLIFY = FALSE)
>
>
> On 8/28/06, Muhammad Subianto <msubianto at gmail.com> wrote:
> > Dear all,
> >
> > I have dataset
> > x <- list(matrix(1:20, 5, 4),matrix(1:20, 5, 4),matrix(1:20, 5, 4))
> > y <- list(matrix(110:114, 5, 1),matrix(110:114, 5, 1),matrix(110:114, 5, 1))
> >
> > I need merge x and y as list (y put in last column).
> > The result is something like
> >
> > [[1]]
> >     [,1] [,2] [,3] [,4]  [,5]
> > [1,]    1    6   11   16   110
> > [2,]    2    7   12   17   111
> > [3,]    3    8   13   18   112
> > [4,]    4    9   14   19   113
> > [5,]    5   10   15   20   114
> >
> > [[2]]
> >     [,1] [,2] [,3] [,4]  [,5]
> > [1,]    1    6   11   16   110
> > [2,]    2    7   12   17   111
> > [3,]    3    8   13   18   112
> > [4,]    4    9   14   19   113
> > [5,]    5   10   15   20   114
> >
> > [[3]]
> >     [,1] [,2] [,3] [,4]  [,5]
> > [1,]    1    6   11   16   110
> > [2,]    2    7   12   17   111
> > [3,]    3    8   13   18   112
> > [4,]    4    9   14   19   113
> > [5,]    5   10   15   20   114
> >
> > I have tried
> > a <- list(x,y)
> > as.data.frame(t(sapply(a, rbind)))
> > lapply(a, function(x) matrix(unlist(x), nrow = length(x), byrow = TRUE))
> > but I don't know how to fix it.
> >
> > Regards, Muhammad Subianto
>
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