[R] out.format for chron

Gabor Grothendieck ggrothendieck at gmail.com
Thu Oct 19 16:38:25 CEST 2006


For your second question:

x <- chron(1)
x <- chron(x, out.format = ddmmyyyy)

using the ddmmyyyy from below.

On 10/19/06, Gabor Grothendieck <ggrothendieck at gmail.com> wrote:
> As discussed the Help Desk article in R News 4/1, the 2 vs 4 year
> length is controlled by the chron.year.abb option,  e.g.
>
>   options(chron.year.abb = FALSE)
>   chron(20)
>
> however, as also discussed there its not really recommended that
> you use this option so try this instead:
>
>   ddmmyyyy <- function( x )
>     with( month.day.year( x ), sprintf( "%02.f-%02.f-%04.f", day,
> month, year) )
>   chron( 20, out.format = ddmmyyyy )
>
>
>
>
> On 10/19/06, Denis Chabot <chabotd at globetrotter.net> wrote:
> > Dear R users,
> >
> > Do you know of a way to precise an out.format for a chron object that
> > would use numbers for months and yet 4 digits for the year?
> >
> > I have tried out.format=c("d-m-year") (note the m instead of either
> > mon or month) but got 27-Feb-1992.
> >
> > Also, the help for chron tells us how to define an out.format when we
> > create a chron object, but how can you change the out.format of an
> > existing chron object?
> >
> > Thanks in advance,
> >
> > Denis
> >
> > ______________________________________________
> > R-help at stat.math.ethz.ch mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
>



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