[R] CI

[Ethan Johnsons]

Thank you so much for the feedback.

The random numbers are working great.  I have tried non-random
numbers, and the outcome is not correct with confint.

Is there a way to compute i.e. a 90% confidence interval for percent of 1?

i.e. where 1 = apple; 2 = orange

> x
 [1] 2 2 2 2 2 1 1 2 2 1 2 1 2 2 2 1 1 1 1 1 1 1 2 2 2
> table (x)
x
 1  2
11 14

> x =11
> confint(lm(x~1), level=0.90)
            5 % 95 %
(Intercept) NaN  NaN

ej

On 10/18/06, Liaw, Andy <andy_liaw at merck.com> wrote:
> Here's one way:
>
> R> x <- c(6,11,5,14,30,11,17,3,9,3,8,8)
> R> confint(lm(x~1), level=.9)
>                  5 %    95 %
> (Intercept) 6.546834 14.2865
>
> Andy
>
> From: Ethan Johnsons
> >
> > I have a quick question, please.
> >
> > Does R have function to compute i.e. a 90% confidence
> > interval for the mean for these numbers?
> >
> > > mean (6,11,5,14,30,11,17,3,9,3,8,8)
> > [1] 6
> >
> > I thought pt or qt would give me the interval, but it seems not.
> >
> > thx much.
> >
> > ej
> >
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> >
> >
> >
>
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