[R] CI

[Liaw, Andy]

Here's one way:

R> x <- c(6,11,5,14,30,11,17,3,9,3,8,8)
R> confint(lm(x~1), level=.9)
                 5 %    95 %
(Intercept) 6.546834 14.2865

Andy 

From: Ethan Johnsons
> 
> I have a quick question, please.
> 
> Does R have function to compute i.e. a 90% confidence 
> interval for the mean for these numbers?
> 
> > mean (6,11,5,14,30,11,17,3,9,3,8,8)
> [1] 6
> 
> I thought pt or qt would give me the interval, but it seems not.
> 
> thx much.
> 
> ej
> 
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