[R] Rank Function

[Gabor Grothendieck]

Because y[1] and y[5] are not the same in Part1 but are in Part2:

> # using y from Part1
> y[5] - y[1]
[1] 1.110223e-16

You could round your numbers to 2 digits, say:

> rank(round(100*y)) # y is from Part1
[1] 3.5 5.0 1.0 2.0 3.5


On 10/10/06, Li Zhang <zhanglitt at yahoo.com> wrote:
> Does anyone know why the two rank functions gives
> different results? I need to use the rank function in
> a "for" loop, so the sequence to be ranked is given
> values in the form of part (1). How can I use
> assignment like in part (1) to get correct ranks as in
> part (2)?
>
> Thank You
>
>
>
> Part (1)
> i<-1.94
> b<-0.95-i
> c<-1.73-i
> d<-2.62-i
>
> y<-c(0.68,0.95,b,c,d)
>
> y
> 0.68  0.95 -0.99 -0.21  0.68
>
> rank(y)
> 3 5 1 2 4
>
> Part(2)
> rank(c(0.68,0.95,-0.99,-0.21,0.68))
> 3.5 5.0 1.0 2.0 3.5
>
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