[R] How to get the function names

[Gabor Grothendieck]

I should have mentioned is that the way it works is that
it uses the name of the list component, if any, otherwise
it uses the name of the function if its given as a number
and otherwise it uses the function itself or possibly the
name of the list.

On 10/5/06, Gabor Grothendieck <ggrothendieck at gmail.com> wrote:
> Probably the best you can hope for is to cover
> most cases.  This one uses match.call and handles
> a number of cases and perhaps if you spend more time
> on it might be able to add some cases where it fails
> such as the second L below:
>
> f <- function(x) {
>        if (!is.list(x)) x <- list(x)
>        if (is.null(names(x))) names(x) <- ""
>        names(x)[names(x) == ""] <- NA
>        mc <- match.call()[-1][[1]]
>        if (length(mc) > 1) mc <- mc[-1]
>        ifelse(is.na(names(x)), as.character(mc), names(x))
> }
>
> f(c(a = mean))
> f(list(a = mean, b = sd))
> f(c(f = function(x)x*x))
> f(list(f = function(x)x*x, function(x)1-x))
> L <- list(a = mean, b = sd)
> f(L)
> L <- list(a = mean, function(x)x)
> f(L)
>
> f(mean)
> f(list(a = mean, sd))
> f(list(mean, sd))
> f(function(x)x*x)
> f(list(function(x)x*x, function(y)y-1))
>
>
> On 10/5/06, Søren Højsgaard <Soren.Hojsgaard at agrsci.dk> wrote:
> > I've defined the function
> >
> > getFunNames <- function(FUN){
> >  if (!is.list(FUN))
> >    fun.names <- paste(deparse(substitute(FUN)), collapse = " ")
> >  else
> >    fun.names <- unlist(lapply(substitute(FUN)[-1], function(a) paste(a)))
> >  fun.names
> > }
> >
> > which gives what I want :
> > > getFunNames(mean)
> > [1] "mean"
> > > getFunNames(ff)
> > [1] "ff"
> > > getFunNames(c(mean,ff))
> > [1] "mean" "ff"
> >
> > If I call this within a function, things go wrong:
> > 1] "FUN"
> > > foo(ff)
> > [1] "FUN"
> > > foo(c(mean,ff))
> > Error in substitute(FUN)[-1] : object is not subsettable
> >
> > Obviously there are some things (quite a few things) which I have not understood. Can anyone help?
> > Thanks
> > Søren
> >
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