[R] String question

[Petr Pikal]

Hi

gregexpr can be used

bits <-"0011011aaa0"
gregexpr("[01]", bits)
[[1]]
[1]  1  2  3  4  5  6  7 11
attr(,"match.length")
[1] 1 1 1 1 1 1 1 1

or

grep("[^01]", bits)
if you want to know that there is any other character then 0 or 1

gregexpr("1", bits)
if you want to know location of 1's

HTH
Petr

On 29 Nov 2006 at 15:06, Carmen Meier wrote:

Date sent:      	Wed, 29 Nov 2006 15:06:08 +0100
From:           	Carmen Meier <carmei3 at web.de>
To:             	R-help <r-help at stat.math.ethz.ch>
Subject:        	[R] String question

> Hi to all
> I would to determinate whether bits is a binary code and I would to
> find out the which bit is set to 1
> 
> bits <-"00110110"
> I found to detect whether there are only numbers
> all.digits(bits)
> but is there any function to detect whether there are only 0 and 1 in
> the string
> 
> And how could I get the f.e the third "bit" from the right hand side
> 
> With regards Carmen
> 
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Petr Pikal
petr.pikal at precheza.cz