[R] String question

[Gabor Grothendieck]

Try:

# TRUE if all 0 and 1
regexpr("^[01]*$", bits) > 0

# positions of 1s
gregexpr("1", bits)[[1]]


On 11/29/06, Carmen Meier <carmei3 at web.de> wrote:
> Hi to all
> I would to determinate whether bits is a binary code and I would to find
> out the which bit is set to 1
>
> bits <-"00110110"
> I found to detect whether there are only numbers
> all.digits(bits)
> but is there any function to detect whether there are only 0 and 1 in
> the string
>
> And how could I get the f.e the third "bit" from the right hand side
>
> With regards Carmen
>
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