[R] keeping dim() for array
Leeds, Mark (IED)
Mark.Leeds at morganstanley.com
Tue Nov 21 14:14:29 CET 2006
I think pip[1,,drop = FALSE] should fix it, but check it to make sure.
-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of Roger Bivand
Sent: Tuesday, November 21, 2006 7:51 AM
To: Federico Calboli
Cc: r-help
Subject: Re: [R] keeping dim() for array
On Tue, 21 Nov 2006, Federico Calboli wrote:
> Hi All,
>
> I noticed the following:
>
> pip = array(1:6, dim = c(3,2))
> dim(pip)
> [1] 3 2
>
> pup = pip[1,]
> dim(pup)
> NULL
>
> I bet there is a *good* reason why one row of an array is
> *dimensionless*, but it's highly inconvenient for my purpose, i.e. to
> use apply() after an array goes through a number of logical steps and
> is redimensioned, sometimes to one single row.
>
> How do I keep dim(pup) to 1 2?
> pup = pip[1,,drop=FALSE]
> dim(pup)
[1] 1 2
R FAQ 7.5, by the way.
>
> Since pup is at the end of a number of if(), it does not necessarily
> end up as one row only, so t(as.matrix(pup)) is the *wrong* answer.
>
> Best,
>
> Federico
>
>
--
Roger Bivand
Economic Geography Section, Department of Economics, Norwegian School of
Economics and Business Administration, Helleveien 30, N-5045 Bergen,
Norway. voice: +47 55 95 93 55; fax +47 55 95 95 43
e-mail: Roger.Bivand at nhh.no
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