[R] Creating a table
Peter Alspach
PAlspach at hortresearch.co.nz
Tue Nov 14 21:51:49 CET 2006
Michael
One solution:
df<-data.frame(loc=c("A","B","A","A","A"),
year=c(1970,1970,1970,1976,1980))
df[,3] <- cut(df$year, c(1969.5,1974.5,1979.5,1984.5),
c('1970-74','1975-79','1980-85'))
with(df, addmargins(table(loc, V3)))
Peter Alspach
> -----Original Message-----
> From: r-help-bounces at stat.math.ethz.ch
> [mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of Michael Graber
> Sent: Wednesday, 15 November 2006 9:21 a.m.
> To: R-Mailingliste
> Subject: [R] Creating a table
>
> Dear R List,
>
> I am a new to R, so my question may be easy to answer for you:
>
> I have a dataframe, for example:
>
> df<-data.frame(loc=c("A","B","A","A","A"),
> year=as.numeric(c("1970","1970","1970","1976","1980")))
>
> and I want to create the following table without using loops:
>
> 1970-74 ; 1975-79 ; 1980-85; rowsum
> A 2 1 1 4
> B 1 0 0 1
> colsum 3 1 1 5
>
> so that the frequencies of df$loc are shown in the table for
> different time intervals.
>
> Thanks in advance for any hint,
>
> Michael Graber
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
______________________________________________________
The contents of this e-mail are privileged and/or confidenti...{{dropped}}
More information about the R-help
mailing list