[R] subsetting a matrix and filling other. Solved

[antonio rodriguez]

antonio rodriguez escribió:
> Christos Hatzis escribió:
>> Use a list to store the partial matrices:
>>
>> z <- vector("list", 189)
>> for(i in 1:189)
>>     z[[i]] <- subset(...)
>>   
> Hi Christos,
>
> I've tried it but it died unexpectedly with a (Killed) message and the 
> linux console prompt again. I think I have enough memory (512) and a 
> pretty good processor (P4, 2.8)
>
> Antonio
>
Hi Christos,

I apologize for the above. Don't know what happen the first time but 
it's OK now

Thanks!

Antonio


>
>
>> -Christos
>>
>> -----Original Message-----
>> From: r-help-bounces at stat.math.ethz.ch
>> [mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of antonio rodriguez
>> Sent: Tuesday, November 07, 2006 2:01 PM
>> To: R-Help
>> Subject: [R] subsetting a matrix and filling other
>>
>> Hi,
>>
>> Having a matrix F(189,6575) I want to do this:
>>
>> z1<-subset(F[,1], F[,1] >= 5 & F[,1] <= 10) .
>> .
>> .
>> z189<-subset(F[,189], F[,189] >= 5 & F[,189] <= 10)
>>
>> I would prefer to have an empty matrix, say 'z' in order to fill its 
>> columns
>> with the output of subsetting F. But each of the subsets can differ in
>> length. It's to say:
>>
>> length(z1)
>> 1189
>>
>> length(z2)
>> 1238
>>
>> Don't know how to set up this with a for loop or the use of apply:
>>
>> z<-189
>> for (i in 1:189)
>> {z[i]<-subset(F.zoo[,i], F.zoo[,i] >= 5 & z1 <= 10)}
>>
>> Error in z[i] <- subset(F.zoo[, i], F.zoo[, i] >= 5 & z1 <= 10) :
>>         nothing to replace with
>>
>> or
>>
>> z<-matrix(0,6575,189)
>> for (i in 1:189)
>> {z[i]<-subset(F.zoo[,i], F.zoo[,i] >= 5 & z1 <= 10)}
>>
>> new error
>>
>>
>> Thanks,
>>
>> Antonio
>>
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>>
>>
>>
>>   
>
>