[R] Help understanding behavior of apply vs sapply
Liaw, Andy
andy_liaw at merck.com
Tue Mar 28 04:31:10 CEST 2006
I'll give it a shot:
apply() is only a wrapper around a for loop through the requested
dimension(s). In this case it would run zls() once for each row in m; i.e.,
twice. The `Value' section of apply() explains what it does if the function
being applied returns vector of length 0.
sapply() is basically lapply() with nice post-processing if possible. It
doesn't know about m being 2x2, just that it's a vector with four elements,
so it's going to call the function four times, and return a list with the
result of each of those calls.
Andy
From: Seth Falcon
>
> Hi,
>
> I was surprised that apply and sapply don't return the same
> results in the example below. Can someone tell me what I'm missing?
>
>
> > zls <- function(x) character(0)
> > m <- matrix(0, nrow=2, ncol=2)
> > apply(m, 1, zls)
> character(0)
> > sapply(m, zls)
> [[1]]
> character(0)
>
> [[2]]
> character(0)
>
> [[3]]
> character(0)
>
> [[4]]
> character(0)
>
>
>
>
>
>
> > R.version
> _
> platform powerpc-apple-darwin8.5.0
> arch powerpc
> os darwin8.5.0
> system powerpc, darwin8.5.0
> status alpha
> major 2
> minor 3.0
> year 2006
> month 03
> day 27
> svn rev 37590
> language R
> version.string Version 2.3.0 alpha (2006-03-27 r37590)
>
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