[R] How to do it without for loops?
Thomas Lumley
tlumley at u.washington.edu
Wed Mar 8 18:05:01 CET 2006
On Wed, 8 Mar 2006, Gabor Grothendieck wrote:
> Thomas' solution is better but thought this might be of interest
> anyways since it can be written closer to mathematical notation.
> That is, the required expression can be written in the
> following equivalent way for a suitable matrix A:
>
> X' diag(u) A' A diag(u) X
Um. n x n matrix? O(n^2) storage? O(n^3) execution time? Yes, it's fine
when n=20, or even 200, but still...
-thomas
> where diag(u) is a diagonal matrix with u along the diagonal
> as in the R diag function, spaces refer to matrix multiplication
> and ' means transpose.
>
> Thus we have:
>
> A <- outer(unique(dat$id), dat$id, "==")
> crossprod(A %*% diag(dat$u) %*% as.matrix(dat[1:2]))
>
>
> On 3/8/06, Thomas Lumley <tlumley at u.washington.edu> wrote:
>> On Wed, 8 Mar 2006, ronggui wrote:
>>
>>> Thank you for all .
>>>
>>> One more question.How can I calculate these efficiently?
>>>
>>> set.seed(100)
>>> dat<-data.frame(x1=rnorm(20),x2=rnorm(20),u=rnorm(20),id=round(2*runif(20)))
>>> # In this example,id's elements are 0,1,2.
>>> y<-list()
>>> for (i in 0:2){
>>> X<-as.matrix(subset(dat,id==i,c("x1","x2")))
>>> u<-as.matrix(subset(dat,id==i,c("u")))
>>> y[[i+1]]<-t(X)%*%u%*%t(u)%*%X
>>> }
>>> y[[1]]+y[[2]]+y[[3]]
>>>
>>
>> People have already told you about crossprod, so crossprod(crossprod(X,u))
>> would seem an obvious improvement over the matrix multiplications.
>>
>> There is a better solution, though.
>>
>> Xu<-dat[,c("x1","x2")]*dat[,"u"]
>> crossprod( rowsum(Xu, dat$id))
>>
>> -thomas
>>
>>
>>> the above code is not elegant.And my second solution to this problem
>>> is using by to get a list.
>>>
>>> matlis<-by(dat, dat$id, function(x){
>>> a<-as.matrix(x[,c("x1","x2")])
>>> b<-as.matrix(x[, "u"])
>>> t(a) %*% b %*% t(b) %*% a
>>> })
>>>
>>> S <- matrix(unlist(matlis), 4, length(matlis))
>>> S1 <- matrix(rowSums(S), 2, 2)
>>>
>>> The code works ,but I want to ask if there is any other more better
>>> ways to do it? It seems that this kind of computation is quite common.
>>>
>>>
>>>
>>>
>>>
>>> 2006/2/28, Gabor Grothendieck <ggrothendieck at gmail.com>:
>>>> Try:
>>>>
>>>> crossprod(x)
>>>>
>>>> or
>>>>
>>>> t(x) %*% x
>>>>
>>>> On 2/28/06, ronggui <ronggui.huang at gmail.com> wrote:
>>>>> This is the code:
>>>>>
>>>>> x<-matrix(rnorm(20),5)
>>>>> y<-list()
>>>>> for (i in seq(nrow(x))) y[[i]]<-t(x[i,,drop=F])%*%x[i,,drop=F]
>>>>> y[[1]]+y[[2]]+y[[3]]+y[[4]]+y[[5]]
>>>>>
>>>>> How can I do it without using for loops?
>>>>> Thank you in advance!
>>>>> --
>>>>> ronggui
>>>>> Deparment of Sociology
>>>>> Fudan University
>>>>>
>>>>> ______________________________________________
>>>>> R-help at stat.math.ethz.ch mailing list
>>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>>> PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
>>>>>
>>>>
>>>
>>>
>>> --
>>> »ÆÈÙ¹ó
>>> Deparment of Sociology
>>> Fudan University
>>>
>>>
>>
>> Thomas Lumley Assoc. Professor, Biostatistics
>> tlumley at u.washington.edu University of Washington, Seattle
>>
>> ______________________________________________
>> R-help at stat.math.ethz.ch mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
>>
>>
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
>
Thomas Lumley Assoc. Professor, Biostatistics
tlumley at u.washington.edu University of Washington, Seattle
More information about the R-help
mailing list