[R] is there a way to let R do smart matrix-vector operation?
Liaw, Andy
andy_liaw at merck.com
Tue Mar 7 00:20:51 CET 2006
It's rarely necessary to have a vector in matrix form. In this case, it
actually make things harder. If B had been a vector, you would have gotten:
> A=matrix(c(2:7), 2, 3)
> B=matrix(c(1, 2), 2, 1)
> A - as.vector(B)
[,1] [,2] [,3]
[1,] 1 3 5
[2,] 1 3 5
Andy
From: Michael
>
> Hi all,
>
> I want to substract vector B from A's each column... how can
> R do that smartly without a loop?
>
> > A=matrix(c(2:7), 2, 3)
> > A
> [,1] [,2] [,3]
> [1,] 2 4 6
> [2,] 3 5 7
> > B=matrix(c(1, 2), 2, 1)
> > B
> [,1]
> [1,] 1
> [2,] 2
> > A-B
> Error in A - B : non-conformable arrays
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide!
> http://www.R-project.org/posting-guide.html
>
>
More information about the R-help
mailing list