[R] index.cond in xyplot
Gabor Grothendieck
ggrothendieck at gmail.com
Thu Aug 10 04:57:31 CEST 2006
That's not a valid specification. See the description of the index.cond
argument in ?xyplot and in particular this part:
If 'index.cond' is a list, it has to be as long as the number of
conditioning variables, and the 'i'-th component has to
be a valid
indexing vector for the integer vector '1:nlevels(g_i)'
(which can, among other things, repeat some of the
levels or drop some altogether).
Thus in your case index.cond is a list with three components and
each of those components can specify a vector of the levels of interest in
the order of interest.
For example, compare the output of these two to get the idea where
CO2 is a builtin data set:
xyplot(conc ~ uptake | Type * Treatment, CO2, index.cond = list(1:2, 1:2))
xyplot(conc ~ uptake | Type * Treatment, CO2, index.cond = list(1:2, 2:1))
On 8/9/06, Taka Matzmoto <sell_mirage_ne at hotmail.com> wrote:
> Dear R-users
>
> I have 5 dependent variables (y1 to y5) and one independent variable (x) and
> 3 conditioning variables (m, n, and 0). Each of the conditioning variables
> has 2 levels. I created 2*4 panel plots.
>
> xyplot(y1+y2+y3+y4+y5 ~ x | m*n*o,layout = c(4,2))
>
> I would like to reorder the 8 panels. I tried to use index.cond (e.g.,
> index.cond = list(c(1,3,2,4,5,7,6,8)) but it didn't work out. I got a error
> message "Error in cond.orders(foo) : Invalid value of index.cond". Please
> let me know if I didn't use index.cond argument properly.
>
> I looked at the example in R-help but all examples have just only one
> conditioning variable.
>
> Is there any way I can arrange the panels in whatever order I want ?
>
> Thanks
>
> Taka
>
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