[R] reshaping data?

[Gabor Grothendieck]

And slightly more to:

table(g = dat$g, val = cut(dat$val, 0:10/10, lab = 1:10/10))

On 9/29/05, Gabor Grothendieck <ggrothendieck at gmail.com> wrote:
> This can be shortened slightly using cut:
>
> table(data.frame(g = dat$g, val = cut(dat$val, 0:10/10, lab = 1:10/10)))
>
> On 9/29/05, Dimitris Rizopoulos <dimitris.rizopoulos at med.kuleuven.be> wrote:
> > you could use something like this (but maybe there are better
> > proposals):
> >
> > dat <- data.frame(g = rep(letters[1:3], each = 5), val = runif(15))
> >
> > out <- do.call(rbind, lapply(split(dat$val, dat$g), function(x){
> >    f <- factor(findInterval(x, vec = seq(0, 1, 0.1)), levels = 1:10)
> >    table(f)
> >    }))
> > colnames(out) <- seq(0.1, 1, 0.1)
> > out
> >
> >
> > I hope it helps.
> >
> > Best,
> > Dimitris
> >
> > ----
> > Dimitris Rizopoulos
> > Ph.D. Student
> > Biostatistical Centre
> > School of Public Health
> > Catholic University of Leuven
> >
> > Address: Kapucijnenvoer 35, Leuven, Belgium
> > Tel: +32/(0)16/336899
> > Fax: +32/(0)16/337015
> > Web: http://www.med.kuleuven.be/biostat/
> >     http://www.student.kuleuven.be/~m0390867/dimitris.htm
> >
> >
> > ----- Original Message -----
> > From: "Karin Lagesen" <karin.lagesen at medisin.uio.no>
> > To: <r-help at r-project.org>
> > Sent: Thursday, September 29, 2005 3:16 PM
> > Subject: [R] reshaping data?
> >
> >
> > >
> > > I have a file like this:
> > >
> > >
> > > a       0.1
> > > a       0.2
> > > a       0.9
> > > b       0.5
> > > b       0.9
> > > b       0.7
> > > c       0.6
> > > c       0.99
> > > c       0.88
> > >
> > > Which I would like to get to be the following matrix:
> > >
> > >      0.1     0.2    0.3    0.4  ...
> > > a     1        2     0       0
> > > b     0        0     0       0
> > > ..
> > >
> > > I.e: each place in the matrix denotes how many entries in each
> > > category that are betwee 0.0 and 0.1, 0.1 and 0.2 and so on.
> > >
> > > The way I was thinking of doing it was by constructing an empty
> > > matrix
> > > and then doing a for loop testing each element and incrementing in
> > > the
> > > matrix as appropriate. However, it struck me that this has to be
> > > easier to do than that. Am I right?
> > >
> > > Karin
> > > --
> > > Karin Lagesen, PhD student
> > > karin.lagesen at medisin.uio.no
> > > http://www.cmbn.no/rognes/
> > >
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