[R] Kolmogorov-Smirnov test help
Berton Gunter
gunter.berton at gene.com
Tue Nov 22 17:24:09 CET 2005
Re: Uwe's advice.
A quote from the late Ellis Ott (a U.S. quality control statistician of the
1970's and 80's):
"Look at your data -- and think!"
Cheers,
-- Bert Gunter
Genentech Non-Clinical Statistics
South San Francisco, CA
"The business of the statistician is to catalyze the scientific learning
process." - George E. P. Box
> -----Original Message-----
> From: r-help-bounces at stat.math.ethz.ch
> [mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of Uwe Ligges
> Sent: Tuesday, November 22, 2005 2:28 AM
> To: lisadowson at gmail.com
> Cc: r-help at stat.math.ethz.ch
> Subject: Re: [R] Kolmogorov-Smirnov test help
>
> Lisa Dowson wrote:
>
> > Hi
> >
> > I am conducting 2-sample Kolmogorov Smirnov tests for my
> Masters project to
> > determine if two independant tree populations have the same
> size-class
> > distribution or not. The trees have been placed into
> size-class categories
> > based on their basal diameters. Once I started running the
> stats on my data,
> > I got confused with the results. Just to show an example of
> what I was
> > testing I ran stats comparing population1 to population 2. and then
> > comparing population 3 to population 2.
> > Popn1 Popn2 Popn3 880 769 0 34 40 19 10 24 19 2 2 8
> 2 2 36 0 0 0
>
> If I interpret your data correctly, we can look at the step
> functions by:
>
> plot.ecdf(x[,1], xlim=c(-10, 900), verticals=TRUE)
> plot.ecdf(x[,2], xlim=c(-10, 900), col.hor="blue", col.vert="blue",
> add=TRUE, verticals=TRUE)
> plot.ecdf(x[,3], xlim=c(-10, 900), col.hor="red", col.vert="red",
> add=TRUE, verticals=TRUE)
>
> and see that there is no good reason why the test should
> reject the Null
> for so few (6!) observations.
>
> Note that you need at least 4 observations in each group to
> be able to
> reject anything at alpha=0.05 even for completely different
> distributions:
>
> ks.test(1:3, 101:103)
>
>
> > Common sense tells me that P1 and P2 are similar and that
> P3 and P2 are
> > dissimilar. However, for the P1 versus P2 test I am getting
> p-value of 1
> > (saying they are strongly similar -what I expected) and for
> the P3 versus P2
> > test, a p-value of 0.9307 (saying they are strongly
> similar, but slightly
> > less similar than the other test- not what I expected at
> all). However,
> > common sense tells me that P3 and P2 are not similar at all
> and that I
> > should be expecting a far lower p-value for the test
> comparing P3 and P2.
>
> Sometimes common sense is dangerous. Sort your data, look again, look
> into the plot, and rethink...
>
> Uwe Ligges
>
>
>
>
> > Any help would be greatly appreciated
> >
> > Thanks
> >
> > Lisa
> >
> > [[alternative HTML version deleted]]
> >
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