[R] a more elegant approach to getting the majority level

[Liaw, Andy]

Don't know if this is more elegant:

names(which.max(table(x)))

Andy

> From: Rajarshi Guha
> 
> Hi, I have a factor and I would like to find the most frequent level.
> 
> I think my current approach is a bit long winded and I was 
> wondering if
> there was a more elegant way to do it:
> 
> x <- factor(sample(1:0, 5,replace=TRUE))
> 
> levels(x)[ which( as.logical((table(x) == max(table(x)))) == TRUE ) ]
> 
> (The length of x will always be an odd number, so I wont get a tie in
> max())
> 
> Thanks,
> 
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